Engineering


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  • Ex: The weight of a person is 60 kg. If he gets 105 calories heat through food and the efficiency of his body is 28%, then upto how much height he can climb (approximately):
    A) 100 m                                      
    B) 200 m
    C) 400 m                                      
    D) 1000 m
    Explanation: 
    Suppose person climbs upto height h, then by using                    
    W=JH | mgh = JQ 
    60×9.8×h = 4.2×(10^5 * 28/100) 
    h = 200 m
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